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ICND1 Subnetting confusion

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evo
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Joined: 2011-09-13
Posts: 1

I was creating some of my own practice subnetting questions and I'm kind of confused here.  I might just be making a mistake, but when I follow the directions as lined out in video 19 i am coming up with some strange results.

For instance, lets say I'm subnetting a class c network 200.15.32.0 and want to create 8 networks.
So I line out my network and host bits like so
128 - 64 - 32 - 16 - 8 - 4 - 2 - 1
0  -  0  -  0  -  0  -  [1  - 0  - 0  -  0]  -  four bit positions to make 8
so I represent these four bits in the binary and convert

11111111 11111111 11111111 11110000
255.255.255.240
256-240 = 16 for my increment, but this gives me 16 networks instead of the 8 that I need.  
The same thing happens when I want to create a subnet with 4 networks.  If I use network sizes that differ from my bit representations (10, 9, 7 etc.), my math comes out right.  Is this just a quirk in the way the math is done or am I doing something wrong?

Thanks for any help!

-Jake

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CiscoMikey
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Joined: 2011-09-14
Posts: 1

Hi Jake

Your not doing anything wrong, keep watching the videos, eventually Jeremy will explain about exceptions to the rule. If I remember rightly he calls them GREAT EXCEPTIONS.

Basically with networks required certain numbers; these being 2,4,8,16,32,64 etc if you req any of these numbers just -1 network.
So 8 network required calculate for 7.

As for hosts req the exception numbers are;3,7,15,31,63 etc.
This time just +1; e.g. 7 Hosts req calculate for 8.

You will find your above calculations work. But the last octect (.240) would end up being .248

All the best

Mike.

Voiper99
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Joined: 2011-09-20
Posts: 2

The issue is that your using four bits for 8 networks when you only need to use three bits.

I believe you are getting confused with the 8 bits used in each octet (128 - 64 - 32 - 16 - 8 - 4 - 2 - 1) - as you can see, 8 is in the fourth position along. However, the actual network formula starts with 2, then goes upwards. In other words, it is:

128 - 64 - 32 - 16 - 8 - 4 - 2

As you can see, 8 is now in the third position along. If you re do your subnetting using this method instead of the one you are currently using, you'll find it works every time.

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